This is the sum of the first six terms of a geometric sequence.
The sum can be written like this:
[tex]-4\frac{1-\left(\frac{1}{2}\right)^6}{1-\frac{1}{2}}=-8\left(1-\dfrac{1}{2^6}\right)\\
=-8\dfrac{63}{64}\\=-\dfrac{63}{8}[/tex]
The correct answer is the second one.
