[tex]\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &8765\\
r=rate\to 5.3\%\to \frac{5.3}{100}\to &0.053\\
t=\textit{elapsed time}\to &5\\
\end{cases}
\\\\\\
A=8765(1-0.053)^5\implies A=8765(0.947)^6[/tex]
