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02-01-2018
Mathematics

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Find the equation of the line normal to f(x)= x -2x^3 at x=1

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02-01-2018

[tex]1 - 6 {x}^{2} = 1 - 6 = - 5 \\ slope \: of \: normal = \frac{1}{5} [/tex]
[tex]f(1) = 1 - 2 = - 1 \\ (1. \: \: - 1)[/tex]
[tex]y + 1 = 3(x - 1)[/tex]

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