ivamiranovic2 ivamiranovic2
  • 04-02-2024
  • Mathematics
contestada

f(x)=2x-8 g(x)=x^(2) Find a value of x such that fg(x)=0.

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jimrgrant1 jimrgrant1
  • 04-02-2024

Answer:

x = ± 2

Step-by-step explanation:

to find f(g(x)), substitute x = g(x) into f(x)

f(g(x))

= f(x²)

= 2x² - 8

Now equate f(g(x)) to zero, that is

2x² - 8 = 0 ( add 8 to both sides )

2x² = 8 ( divide both sides by 2 )

x² = 4 ( take square root of both sides )

[tex]\sqrt{x^2}[/tex] = ± [tex]\sqrt{4}[/tex] , that is

x = ± 2

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