Answer:
False
Step-by-step explanation:
The given equation is:
[tex]2sin^2x-sinx-1[/tex]
Substituting x=[tex]\frac{3\pi}{2}[/tex] in the above given equation, we have
=[tex]2sin(\frac{3\pi}{2})^2-sin(\frac{3\pi}{2})-1[/tex]
=[tex]2(-1)^2-(-1)-1[/tex]
=[tex]2+1-1[/tex]
=[tex]2[/tex]
Thus, the value of the given equation by substituting the value of x is equal to 2 and not zero, therefore the given statement is false.
