03-04-2017
Mathematics

contestada

. Solve (cos x)(cos 2x) = 0 for the interval [0, ππ]
x = π/3, x = π/2
x = π/3, x = π/4, x = π/6
x = π/4, x = π/2, x = 3π/4
x = 3 π/4, x = π

Respuesta :

ghanami ghanami

06-04-2017

hello :
(cos x)(cos 2x) = 0

(cos x= 0)0r(cos 2x =0)
sur : [0, π]
1) cos x= 0 : x = π/2
2 ) cos 2x =0 : x = π/4 or x=3π/4
conclusion : x = π/4, x = π/2, x = 3π/4

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