Given:
The two sides and angle of triangle are
[tex]\begin{gathered} a=19m \\ b=25m \\ \angle C=65\degree \end{gathered}[/tex]
Required:
To find the value of X.
Explanation:
By cosine rule
[tex]\begin{gathered} X=\sqrt{a^2+b^2-2ab\cos C} \\ \\ =\sqrt{19^2+25^2-2\times19\times25\cos65} \\ \\ =24.17m \end{gathered}[/tex]
Final Answer:
The value of X is
[tex]X=24.17m[/tex]
