ANSWER:
[tex]x=5,=-3[/tex]
STEP-BY-STEP EXPLANATION:
We have the following equation:
[tex]x^2-2x-15[/tex]
We solve by factoring. We look for two numbers that product -15 and the sum is equal to -2:
[tex]\begin{gathered} 3\cdot-5=-15 \\ 3+(-5)=-2 \\ \text{Therefore:} \\ (x+3)\cdot(x-5)=0 \\ x+3=0\rightarrow x=-3 \\ x-5=0\rightarrow x=5 \end{gathered}[/tex]
