The balanced equation is:
[tex]Mg_{(s)}+H_2O_{(g)}\to MgO_{(s)}+H_{2(g)}[/tex]
The first step is to convert the given mass of magnesium to moles (MW=24.3g/mol):
[tex]1g\cdot\frac{1mol}{24.3g}=0.04mol[/tex]
Now, use the ratio given by the chemical equation:
[tex]0.04molMg\cdot\frac{1molMgO}{1molMg}=0.04molMgO[/tex]
Now, use the molecular weight of magnesium oxide to convert it to grams (MW=40.3g/mol):
[tex]0.04mol\cdot\frac{40.3g}{1mol}=1.612g[/tex]
The maximum mass of magnesium oxide produced is 1.612g.
