Answer:
Step by step explanation:
In order to find the axis of symmetry, we will have to find the x-value of the vertex
[tex]\text{Vertex = }\lbrack\frac{-b}{2a},\text{ f(}\frac{-b}{2a})\rbrack[/tex][tex]x^2\text{ + 4x +6}[/tex]a = 1
b = 4
c = 6
[tex]\text{Vertex = }\lbrack\frac{-4}{2},f(\frac{-4}{2})\rbrack[/tex][tex]Vertex=\lbrack-2,f(-2)\rbrack\text{ }[/tex]We have found the x-value of the vertex which is -2
Line/axis of symmetry is x=-2
