we have the equation
[tex]x^2+3x+12=0[/tex]
Solve using the formula
a=1
b=3
c=12
substitute
[tex]x=\frac{-3(+-)\sqrt{3^2-4(1)(12)}}{2(1)}[/tex][tex]x=\frac{-3(+-)\sqrt{-39}}{2}[/tex]
Remember that
i^2=-1
so
[tex]x=\frac{-3(+-)i\sqrt{39}}{2}[/tex]
The answer is the fourth option
