Solution
For this case we can start doing this:
[tex]5\frac{2}{3}=\frac{5\cdot3+2}{3}=\frac{17}{3}[/tex]and then we can find the are on this way:
[tex]A=\frac{17}{3}yd\cdot4yd=\frac{68}{3}yd^2[/tex]And we can rewrite this expression as:
[tex]22\frac{2}{3}[/tex]