Vertex of parabola. ax^2 + bx + c
its defined by
x = ( -b/2a)
y = (4ac - b^2)/. 4a
Now find equation of parabola y = ax^2 + bx + c
ROOTs of parabola are
x = -6 ,. and. x= -2
Then multiply now
(x + 6) • (x +2 ) = x^2 + 8x + 12
THEN find a,b,c
a = 1,
b= 8
c= 12
Now finally find Vertex
Vertex = ( -8/2. , 4•12- 8^2/4)
Vertex = (-4 , -4)
So then coordinates for Vertex are
x = -4
y = -4
