The quadratic regression equation for the stream of water is [tex]y=-0.139x^{2} +1.667x[/tex] {parabola}
Given that the water stream produced by fountain is parabola
Vertex of parabola is (6,5) , parbola is facing downward,axis of symmetry of parabola is x=6 and parabola passes through (0,0)
according to symmetry the third point on the parabola is (12,0)
General equation for a parabola⇒ Y=-4a[tex]X^{2}[/tex]
⇒(y-5)=-4a[tex](x-6)^{2}[/tex] { as the Vertex of parabola is (6,5) }
⇒(y-5)=-4a([tex]x^{2} +36-12x[/tex])
subtituting (0,0) in the equation to get the value of a
⇒-5=-4a(36)
⇒ a=[tex]\frac{-5}{144}[/tex]
equation of parabola⇒(y-5)=-4( [tex]\frac{5}{144}[/tex])[tex](x-6)^{2}[/tex]
Therefore,The quadratic regression equation for the stream of water is [tex]y=-0.139x^{2} +1.667x[/tex]
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