Hi there!
We can use the rotational equivalent of Newton's Second Law:
[tex]\huge\boxed{\Sigma \tau = I \alpha}[/tex]
Στ = Net Torque (Nm)
I = Moment of inertia (kgm²)
α = Angular acceleration (rad/sec²)
We can plug in the given values to solve.
[tex]\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}[/tex]
