So if Jacob works x shifts, he works for a total of [tex]2 \frac{1}{2} [/tex] hours, and each shift is [tex] \frac{3}{4} [/tex] hours, the equation can be set up as;
[tex]2 \frac{1}{2} =x* \frac{3}{4} \\( \frac{4}{3} )*2 \frac{1}{2} =(x* \frac{3}{4})*( \frac{4}{3} )\\ \frac{4}{3} * \frac{5}{2} =x\\x= \frac{20}{6} =3 \frac{1}{3} [/tex]
So Jacob worked [tex]3 \frac{1}{3} [/tex]shifts
