Answer:
A
Step-by-step explanation:
Using the altitude- on- hypotenuse theorem
(leg of big Δ )² = (part of hypotenuse below it ) × ( whole hypotenuse) , so
x² = 4 × (4 + 8) = 4 × 12 = 48 ( take square root of both sides )
x = [tex]\sqrt{48}[/tex] = [tex]\sqrt{16(3)}[/tex] = 4[tex]\sqrt{3}[/tex] → A
