Answer:
pOH = 11
Explanation:
The pH is an unit of concentration widely used in chemistry to find the quality of a solution.
To solve this question we must, as first, find the [H+] using the pH:
[H+] = 10^-pH
[H+] = 10^-3
Now, using kw:
kw = 1.0x10-14 = [H+] [OH-]
1.0x10-14 = [10^-3] [OH-]
[OH-] = 1.0x10-11
pOH = -log [OH-]
pOH = 11
