yas
so
(x-h)^2=4p(y-k)
(h,k) is vertex
p is distance from directix to vertex, also distance from focus point to vertex
given
(x-0)^2=4(2)(y-0)
since x is the square term, the parabola opens up or down
center is (0,0)
the distance to the focus is 2 units
since 2 is positive, it opens up, meaning the focus is above the vertex
the focus is 2 units above (0,0)
te focus is (0,2)
answer is 3rd option
