Answer:
0.29 J/g.°C
Explanation:
Step 1: Given data
- Mass of the substance (m): 25.0 g
- Initial temperature: 92.6 °C
- Final temperature: 99.4 °C
Step 2: Calculate the temperature change (ΔT)
ΔT = 99.4 °C - 92.6 °C = 6.8 °C
Step 3: Calculate the specific heat of the substance (c)
We will use the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C
