Here's the solution,
The given triangle is an equilateral triangle, because it's all angles measure 60° each
now,
Area of an equilateral triangle :
=》
[tex] \dfrac{ \sqrt{3} }{4} {a}^{2} [/tex]
where,
=》
[tex] \dfrac{ \sqrt{3} }{4} \times 8 \times 8[/tex]
=》
[tex] \sqrt{3} \times 16[/tex]
=》
[tex]16 \sqrt{3} \: \: \: cm {}^{2} [/tex]
or
=》
[tex]27.71 \: \: cm {}^{2} [/tex]
