Answer: 50.7 J
Explanation:
Given
mass of lion is [tex]m=2.6\ kg[/tex]
The initial speed of the lion is [tex]v_1=5\ m/s[/tex]
increased speed of lion is [tex]v_2=8\ m/s[/tex]
Initially, its kinetic energy is [tex]K_1=\frac{1}{2}mv_1^2[/tex]
Final kinetic energy [tex]k_2=\frac{1}{2}mv_2^2[/tex]
work did by lion after speed up is [tex]k_2-k_1[/tex]
[tex]\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J[/tex]
