Answer:
840
Step-by-step explanation:
Given the date:
Birth date = 12/24/2002
Number of digits = 8 = 8! = (8*7*6*5*4*3*2*1) = 40320
Repeated digits :
digit 2 = 4 times = 4! = (4 * 3 *2 * 1) = 24
digit 0 = 2 times = 2! = 2*1 = 2
Therefore the number of 8 digit codes that can be formed is :
8! / (4! * 2!)
40320 / (24 * 2)
40320 / 48
= 840
Hence, 840 8 digit codes can be formed
