zbrown87 zbrown87
  • 01-03-2021
  • Mathematics
contestada

What are the roots of the equation x^2-6x+58=0 in simplest a+bi form?

Respuesta :

irspow
irspow irspow
  • 01-03-2021

Answer:

Step-by-step explanation:

[tex]x^2-6x+58=0\\ \\ \text{Since the discriminant, 36-232<0, there are no real roots, only two imaginary ones.}\\ \\ x=3\pm 7i\\ \\ (x+3+7i)(x+3-7i)[/tex]

Answer Link

Otras preguntas

[100+(586+40/10)]/5<19
five sixths plus one twelfths
Is new York City a rural urban or suburban community explain
explain how you can use a number line to show that 3/6 and 1/2 are eguivalent fractions
How do you covert oz to pt
two friends share 3 fruit bars equally how much does each person get
which force gravitational or electrical repels as well as attracts?
simplify 4y-28=2(y+2)
22x-14y=65 linear or non linear?
can y'all describe a chinese estate? asap