Vertex is = (8, -1)
Axis of symmetry : x = 8
We first write the given equation in vertex form.
[tex]y=x^{2} -16x+63\\y=x^2-2(8)x+64-1\\y=(x^2-2(8)x+8^2)-1\\y=(x-8)^2-1[/tex]
Compare it with [tex]y=a(x-h)^2+k[/tex].
So vertex= (h, k) = (8, -1).
Axis of symmetry passes through the vertex and parallel to the y-axis.
So the equation of the axis of symmetry is x = 8.
Learn more: https://brainly.com/question/9201543
