Answer:
P(not T ) = 0.51
Step-by-step explanation:
Step(i):-
Given that the R and T are two mutually exclusive events
P(R∩T) = 0
Addition theorem on probability
P(RUT) =P(R)+P(T) - P(R∩T)
P(RUT) =P(R)+P(T) - 0
P(RUT) =P(R)+P(T)
Step(ii):-
Given P(R) = 0.2 and P(RUT) = 0.69
P(RUT) =P(R)+P(T)
P(T) = P(RUT) -P(R) = 0.69 -0.2
P(T) = 0.49
P(not T) = 1- P(T)
P(not T ) = 1 - 0.49 = 0.51
Final answer:-
P(not T ) = 0.51
