Answer:
[tex]\huge\boxed{y=1\dfrac{1}{3}=\dfrac{4}{3}}[/tex]
Step-by-step explanation:
[tex]y-\dfrac{4}{12}=1\\\\y-\dfrac{4:4}{12:4}=1\\\\y-\dfrac{1}{3}=1\qquad|\text{add }\dfrac{1}{3}\ \text{to both sides}\\\\y-\dfrac{1}{3}+\dfrac{1}{3}=1+\dfrac{1}{3}\\\\y=1\dfrac{1}{3}[/tex]
