Answer:
[tex]\huge\boxed{x=\dfrac{7}{5}\to x=1\dfrac{2}{5}}[/tex]
Step-by-step explanation:
[tex]2(1-5x)+4=-8\qquad|\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup(1-5x)}{2\!\!\!\!\diagup}+\dfrac{4\!\!\!\!\diagup}{2\!\!\!\!\diagup}=\dfrac{-8\!\!\!\!\diagup}{2\!\!\!\!\diagup}\\\\1-5x+2=-4\\\\-5x+3=-4\qquad|\text{subtract 3 from both sides}\\\\-5x=-7\qquad|\text{divide both sides by (-5)}\\\\x=\dfrac{7}{5}[/tex]
