Answer:
a∈R
Step-by-step explanation:
Use the distributive property to multiply 3 by 2a+3.
6a+9−2a=2(5+2a)−1
Combine 6a and −2a to get 4a.
4a+9=2(5+2a)−1
Use the distributive property to multiply 2 by 5+2a.
4a+9=10+4a−1
Subtract 1 from 10 to get 9.
4a+9=9+4a
Subtract 4a from both sides.
4a+9−4a=9
Combine 4a and −4a to get 0.
9=9
Compare 9 and 9.
True
This is true for any a.
a∈R
