Answer:
d= 5√5
Step-by-step explanation:
[tex]d =:\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\(-7,3)=(x_1,y_1)\\(4,5)=(x_2,y_2)\\\\d = \sqrt{(4-(-7))^2+(5-3)^2}\\\\d = \sqrt{(4+7)^2+(5-3)^2}\\\\d = \sqrt{(11)^2+(2)^2}\\\\d = \sqrt{121+4}\\\\d = \sqrt{125}\\\\d =5 \sqrt{5}[/tex]
