Answer:
x=0, x=2 or x=-2
Step-by-step explanation:
Hello, please consider the following.
[tex]\dfrac{x^3-4x}{x^2+2x+1}=\dfrac{x(x^2-4)}{(x+1)^2}\\\\=\dfrac{x(x-2)(x+2)}{(x+1)^2}[/tex]
So to get this expression equal to zero it means x=0, x=2 or x=-2
The correct answer is the last one.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
