tbird1270 tbird1270

01-08-2020
Mathematics

contestada

Compute the values of dy and Δy for the function y=e^(2x)+6x given x=0 and Δx=dx=0.03.

Respuesta :

sqdancefan sqdancefan

01-08-2020

Answer:

dy = 8·dx
Δy = 0.24

Step-by-step explanation:

The derivative of your function is ...

y' = dy/dx = 2e^(2x) +6

At x=0, the value is ...

y'(0) = 2e^0 +6 = 8

dy = 8·dx

__

Δy = y'(0)·Δx

Δy = 8(.03)

Δy = 0.24

Answer Link

Otras preguntas

If you wanted to share a statement of the company's financial position at a certain time, you would use a _____. balance sheet line graph personal budget databa

The atmosphere is heated most by which of the following? A. Convection B. Radiation C. Wind D. Conduction

A seafood company produces cans of tuna. Each can gets wrapped with a paper label. If every van has a radius of 8.3 centimeters, what is the approximate length

What decimal is written in words five and four hundred sixty seven ten thousandths

Why do the cowboys sing at night? This is from the little house on the prairie?

what 3 words are at the beginning of every scale

Newton's 2nd law of motion

What is the suffix in the word “disqualification”?

What is the multiple zero and multiplicity of f(x)=(x+8)(x+8)(x-3)(x+8)

which of the following statements about interest groups are true