Answer:
[tex]E(x) =\sum_{i=1}^n X_i P(X_i)[/tex]
And replacig we got:
[tex]E(x) = 4*0.25 +5*0.6 +6*0.15= 4.9[/tex]
Step-by-step explanation:
For this case we have the following distribution function
x 4 5 6
p(x) 0.25 0.6 0.15
And we want to find the mean of the distributuon and we can use the following formula:
[tex]E(x) =\sum_{i=1}^n X_i P(X_i)[/tex]
And replacig we got:
[tex]E(x) = 4*0.25 +5*0.6 +6*0.15= 4.9[/tex]
