Answer:
See below.
Step-by-step explanation:
First check that f(x) has a real value at x = 3:
f(3) = 3^2 + 5(3 - 2)^7
= 9 + 5 * 1^7
= 14,
So the first condition is met.
Now we check if limit as x approaches 3 exists.
As x approaches 3 from below f(x) approaches 14 and at x = 3 = 14.
As x approaches 3 from above f(x) approaches 14 and at x = 3 = 14.
These 3 conditions shows that f(x) is continuous at x = 3.
