The distance between two (4, 6) and (5, 0) is 6.08 units.
Solution:
The given points are (4, 6) and (5, 0).
[tex]x_1=4, y_1=6, x_2=5, y_2=0[/tex]
To find the distance between two points:
Distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(5-4)^2+(0-6)^2}[/tex]
[tex]d=\sqrt{1^2+(-6)^2}[/tex]
The value of 1² = 1
The value of (–6)² = 36
[tex]d=\sqrt{1+36}[/tex]
[tex]d=\sqrt{37}[/tex]
d = 6.08
The distance between two (4, 6) and (5, 0) is 6.08 units.
