Answer:
2MNO4 + 10 I- + 16 H+ → 5 I2 + 2 Mn 2+ + 8 H20
Explanation:
2 MnVII + 10 e- → 2 MnII ( reduction reaction)
10 I-I - 10 e- → 10 I° (oxidation)
MnO4- is an oxidizing agent, I- is a reducing agent.
This is a redox reaction. A redox reaction can be described as a reaction in which oxidation as well as reduction are taking place. One of the atoms is being reduced while the other one is being oxidized.
