Answer:
x=5
Step-by-step explanation:
we have
[tex]3(x+2)+x=2x+16[/tex]
Solve for x
Distribute left side
[tex]3x+6+x=2x+16[/tex]
Combine like terms left side
[tex]4x+6=2x+16[/tex]
Group terms that contain the same variable
[tex]4x-2x=16-6\\2x=10\\x=5[/tex]
therefore
For x=5
The equation is true
Verify
substitute the value of x=5 in the original expression and evaluate
[tex]3(5+2)+5=2(5)+16[/tex]
[tex]3(7)+5=10+16[/tex]
[tex]26=26[/tex] ----> is true
