Answer:
16
Step-by-step explanation:
[tex]\text{Put the values of }\ x=\dfrac{1}{2}\ \text{and}\ y=-5\ \text{to the expression}\ 4x^2-3y:\\\\4\left(\dfrac{1}{2}\right)^2-3(-5)\qquad\text{use PEMDAS}\\\\=4\left(\dfrac{1}{2}\right)\left(\dfrac{1}{2}\right)+(-3)(-5)\\\\=4\!\!\!\!\diagup\left(\dfrac{1}{4\!\!\!\!\diagup}\right)+15\\\\=1+15\\\\=16[/tex]
