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  • 02-09-2019
  • Mathematics
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If f(x) = 8sin(x2)+4, where x is measured in radians, then what is the slope of f(x) at x = 2?​

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Аноним Аноним
  • 02-09-2019

The slope of f(x) at x = 2 is the value of the first derivative f'(x) at x = 2.

So, we have

[tex]f'(x) = 8\cos(x^2)\cdot 2x = 16x\cos(x^2)[/tex]

which implies

[tex]f'(2)=16\cdot 2\cos(4)=32\cos(4)[/tex]

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