Answer:
d=5.39 units
Step-by-step explanation:
Given A (-3, -2)
T= (x+5, y-3)
T= (-3+5, -2-3)
T=(2,-5)
Applying the translation on;
A( -3,-2)
A' (-3+2, -2+ -5)
A'= (-1, -7)
Distance
d= [tex]\sqrt { X2-X1)^2 + (Y2-Y1)^2[/tex]
A = (-3,-2) and A'(-1, -7)
d=√ (-1--3)² + (-7--2)²
d=√ (2)²+(-5)²
d=√4+25
d=√29
d=5.39 units
