Answer:
[tex]\large\boxed{-\dfrac{4}{2}=-2}[/tex]
Step-by-step explanation:
[tex]a_1,\ a_2,\ a_3,\ a_4,\ ...-\text{geometric sequence}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...-\text{common ratio}\\\\======================\\\\\text{We have}\\\\-2,\ 4,\ -8,\ 16,\ -32,\ ...\\\\\text{The common ratio:}\\\\\dfrac{4}{-2}=-2\\\\\dfrac{-8}{4}=-2\\\\\dfrac{16}{-8}=-2\\\\\dfrac{-32}{16}=-2[/tex]
