[tex]4x^{2} -4x - 1 = 0[/tex]
To solve for the zeros you can use the quadratic formula:
[tex]\frac{-b plus/minus\sqrt{b^{2}-4ac } }{2a}[/tex]
a = 4
b = -4
c = -1
[tex]\frac{-(-4) plus/minus\sqrt{(-4)^{2}-4(4)(-1) } }{2(4)}[/tex]
[tex]\frac{4 plus/minus\sqrt{16+16 } }{8}[/tex]
[tex]\frac{4plus/minus\sqrt{32} }{8}[/tex]
[tex]\frac{4plus/minus4\sqrt{2 } }{8}[/tex]
[tex]\frac{1 plus/minus\sqrt{2} }{2}[/tex]
Hope this helped!
~Just a girl in love with Shawn Mendes
