Answer:
Factoring
Step-by-step explanation:
To solve the equation [tex]x ^ 2 + 4x + 3 = 0[/tex], you must apply the factoring method.
You must find two real numbers b and c such that:
[tex]b + c = 4[/tex]
and
[tex]b(c) = 3[/tex]
Then the expression:
[tex]x ^ 2 + 4x + 3 = 0 = (x + b)(x + c)[/tex]
You can prove that:
[tex]b = 3\\c = 1[/tex]
So
[tex]x ^ 2 + 4x + 3 = 0 = (x + 3)(x + 1)[/tex]
[tex](x + 3)(x + 1) = 0[/tex]
[tex]x +3 = 0[/tex] or [tex]x + 1 = 0[/tex]
[tex]x = -3[/tex] or [tex]x = -1[/tex]
