Answer: 4.74 moles
Explanation:
2LiBr+Ba\rightarrow BaBr_2+2Li
Moles of Ba=\frac{\text {given mass}}{\text {molar mass}}
Moles of Ba=\frac{325g}{137g/mol}=2.37 moles
According to given balanced equation,
1 mole of Barium gives 2 moles of Li
Thus 2.37 moles of Barium gives=\frac{2}{1}\times 2.37=4.74 moles
Thus 4.74 moles of lithium will be produced by 135 g of barium.
