[tex]\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=\cfrac{3}{5}(x-4)\implies y+6=\cfrac{3}{5}(x-4)[/tex]
