Hi there!
Let's solve this equation step by step!
[tex] {x}^{2} + 26x + 48 = 0[/tex]
First factor the equation. To do this we're looking for two numbers with a product of 48 and a sum of 26. We find the numbers 24 and 2. Let's factor!
[tex](x + 24)(x + 2) = 0[/tex]
Now use the rule AB = 0 gives A = 0 or B = 0.
We find the following:
[tex]x + 24 = 0 \: \: or \: \: x + 2 = 0[/tex]
And finally subtract.
[tex]x = - 24 \: \: or \: \: x = - 2[/tex]
~ Hope this helps you!
